Multivariable Calculus (Calc III) - Complete Semester Course - Multivariable Calculus: Distance from a point to a plane
4.0(4)
42 learners
What you'll learn
This course includes
29.5 hours of video
Certificate of completion
Access on mobile and TV
Summary
Full Transcript
In this exercise, we find the distance from the point (1, 2, 3) to the plane 3x - y + 5z = 2 using geometric methods. We start by identifying another point on the plane and connect it to our given point with a vector v. We then project v onto a line perpendicular to the plane by projecting it on the normal vector n derived from the plane's equation. The distance is calculated as the absolute value of the dot product of v and n divided by the magnitude of N. This approach emphasizes understanding vector projections for solving various distance problems in geometry without relying on specific formulas.
#mathematics #math #vectorcalculus #multivariablecalculus #linesandplanes #iitjammathematics #calculus3
Continue this lesson in the app
Install CourseHive on Android or iOS to keep learning while you move.