Summary
Full Transcript
📘 Welcome to Part 212 of Code & Debug’s DSA in Python Course! This session solves “Minimum Insertion Steps to Make a String Palindrome.” The key insight: the fewest insertions equals n − LPS(s), where LPS is the Longest Palindromic Subsequence length. We’ll cover both the elegant LCS/LPS reduction and the classic interval DP formulation, with complete Python walkthroughs. 🔗 LeetCode – Minimum Insertion Steps to Make a String Palindrome: https://leetcode.com/problems/minimum-insertion-steps-to-make-a-string-palindrome/description/ 🔗 Companion Reading (LPS/LCS approach and interval DP): https://codeanddebug.in/blog/minimum-insertion-steps-to-make-a-string-palindrome/ 📄 FULL Playlist Sheet (All Videos in Order): https://docs.google.com/spreadsheets/d/1AWE15Fy3wD2iqu2vjK_R7cCiuvSsjYQclcdZmHpF66o/edit?usp=sharing 🎓 Enroll Free: Master Python DSA Course https://codeanddebug.in/course/master-dsa-with-leetcode 🚀 Advance Python DSA for FAANG (Zero to Hero Course) https://codeanddebug.in/course/zero-to-hero-python-dsa Stay focused and keep coding with Code & Debug. Like | Share | Subscribe | Hit the 🔔 #MinimumInsertionsPalindrome #LeetCode1312 #LPS #LCS #StringDP #IntervalDP #DynamicProgramming #Memoization #Tabulation #SpaceOptimization #PythonDSA #CodeAndDebug #Part212 #InterviewPrep
