Summary
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🚀 Welcome to Part 111 of Code & Debug’s DSA in Python Course! In this lecture, we solve Leetcode 543: Diameter of Binary Tree, where we calculate the longest path between any two nodes in a binary tree. We use an efficient DFS-based solution that calculates height and updates the diameter simultaneously. 📚 What you’ll learn in this video: ✅ Understanding what the diameter of a binary tree means ✅ Why we need to calculate height + diameter together ✅ Optimized DFS approach with a class-level variable ✅ Python implementation with dry run explanation ✅ Time and space complexity analysis 👉 Practice the problem on Leetcode: 🔗 https://leetcode.com/problems/diameter-of-binary-tree/ 👉 Refer to the article for better understanding: 📌 https://codeanddebug.in/blog/diameter-of-binary-tree/ 👉 📄 Access the full YouTube DSA Playlist Sheet (All Questions in Order): 🔗 https://docs.google.com/spreadsheets/d/1AWE15Fy3wD2iqu2vjK_R7cCiuvSsjYQclcdZmHpF66o/edit?usp=sharing 👉 Enroll in this FREE DSA Python course here: 🔗 https://codeanddebug.in/course/master-dsa-with-leetcode 👉 Enroll for Self-Paced Advanced DSA course here: 🔗 https://codeanddebug.in/course/zero-to-hero-python-dsa 🙏 Thank you for supporting Code & Debug! Don’t forget to like, share, and subscribe to our channel. Hit the 🔔 bell icon to stay updated with our latest lectures. #DiameterOfBinaryTree #DFS #BinaryTree #TreeRecursion #Leetcode543 #PythonDSA #DSAPythonCourse #CodeAndDebug #CodingInterviews #Part111
