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📘 Welcome to Part 213 of Code & Debug’s DSA in Python Course! In this video, the goal is to compute the minimum deletions needed to make two strings identical. The key insight is to leverage the Longest Common Subsequence: minimum deletions = len(word1) + len(word2) − 2 × LCS(word1, word2). Everything not in the LCS must be deleted from one side or the other. We’ll implement LCS via memoization, tabulation, and a space-optimized rolling array. 🔗 LeetCode – Delete Operation for Two Strings: https://leetcode.com/problems/delete-operation-for-two-strings/description/ 🔗 Companion Reading (Article with Code & Explanations): https://codeanddebug.in/blog/delete-operation-for-two-strings/ 📄 FULL Playlist Sheet (All Videos in Order): https://docs.google.com/spreadsheets/d/1AWE15Fy3wD2iqu2vjK_R7cCiuvSsjYQclcdZmHpF66o/edit?usp=sharing 🎓 Enroll Free: Master Python DSA Course https://codeanddebug.in/course/master-dsa-with-leetcode 🚀 Advance Python DSA for FAANG (Zero to Hero Course) https://codeanddebug.in/course/zero-to-hero-python-dsa Stay focused and keep coding with Code & Debug. Like | Share | Subscribe | Hit the 🔔 #DeleteOperationForTwoStrings #LeetCode583 #LCS #DynamicProgramming #StringDP #Memoization #Tabulation #SpaceOptimization #PythonDSA #CodeAndDebug #Part213 #InterviewPrep
