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📘 Welcome to Part 225 of Code & Debug’s DSA in Python Course! Given a valid parentheses string, the task is to return its maximum nesting depth. The optimal approach is a single linear scan with a depth counter: increment on '(', update a running maximum, and decrement on ')'. This avoids stacks and yields O(n) time and O(1) extra space. 🔗 LeetCode – Maximum Nesting Depth of the Parentheses: https://leetcode.com/problems/maximum-nesting-depth-of-the-parentheses/description/ 🔗 Companion Reading (Step-by-step with code): https://codeanddebug.in/blog/maximum-nesting-depth-of-the-parentheses/ 📄 FULL Playlist Sheet (All Videos in Order): https://docs.google.com/spreadsheets/d/1AWE15Fy3wD2iqu2vjK_R7cCiuvSsjYQclcdZmHpF66o/edit?usp=sharing 🎓 Enroll Free: Master Python DSA Course https://codeanddebug.in/course/master-dsa-with-leetcode 🚀 Advance Python DSA for FAANG (Zero to Hero Course) https://codeanddebug.in/course/zero-to-hero-python-dsa Stay focused and keep coding with Code & Debug. Like | Share | Subscribe | Hit the 🔔 #MaximumNestingDepth #LeetCode1614 #Parentheses #DepthCounter #StackAlternative #PythonDSA #CodeAndDebug #Part225 #InterviewPrep
