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LeetCode 338. Counting Bits β return an array where ans[i] is the number of 1s in the binary representation of i. In this video youβll learn: The key DP pattern for bit counts The recurrence and why it works How to implement it in O(n) time Complexity and edge cases DP idea (reuse previous results): ans[i] = ans[i / 2] + (i & 1) (integer division by 2 drops the last bit; add 1 if the last bit is 1) Alternative equivalent recurrence: ans[i] = ans[i & (i - 1)] + 1 Complexity: Time: O(n) Extra space: O(1) (excluding the output array) Leetcode playlist: https://www.youtube.com/playlist?list=PLF0G-7pZcOza_jyAxwMpa5KnK3vST5smK Subscribe: youtube.com/channel/UCdKpV0t_sLv9gUsxHOYrt7g?sub_confirmation=1 #LeetCode #DynamicProgramming #BitManipulation #CodingInterview #CPlusPlus #LeetCode #DynamicProgramming #BitManipulation #CodingInterview #CPlusPlus #leetcode #leetcodecoding #leetcodesolution #leetcodechallenge #faang #fang #computerscience #cs #codingtiktok #coding #codinglife #boostofhope #fyp #codinginterview #softwareengineer #swe #tech #foryou #python #learntocode #google #techtok #programming #algorithms #learntocode @reper #foryou #viral #reper #urmaritori #for
