LeetCode 75 C++ | Step-by-Step Solutions (LAN Academy) - LC 1318 — Minimum Flips (OR Truth Table)

This problem looks tricky… until you realize it’s just a per-bit truth table. In this video, we compute the minimum flips in a and b so that (a OR b == c) — clean, fast, interview-ready. Key insight (the whole solution): For each bit, compare (ai, bi, ci): - If ci == 0: both ai and bi must be 0 → flips += ai + bi (flip any 1s to 0) - If ci == 1: at least one of ai or bi must be 1 → if ai == 0 and bi == 0 then flips += 1 No brute force. No building strings. Just bit operations in one pass. What you’ll learn: • How to reason per bit using a simple truth table • The exact flip rules for ci = 0 vs ci = 1 • A clean C++ implementation (loop over 0..31 bits) • Complexity + common edge cases Examples: a=2, b=6, c=5 → 3 flips a=4, b=2, c=7 → 1 flip a=1, b=2, c=3 → 0 flips Problem link: https://leetcode.com/problems/minimum-flips-to-make-a-or-b-equal-to-c/ More C++ LeetCode explanations: https://lanacademy-school.thinkific.com/courses/leetcode75 Question: What’s your first instinct for bit problems — truth table, masks, or brute force? Comment your approach. Follow LAN Academy: Website: https://lanacademy-school.thinkific.com YouTube: @lanacademy9521 X (Twitter): https://x.com/SolutionsLan #LeetCode #cpp #BitManipulation#leetcode #leetcodecoding #leetcodesolution #leetcodechallenge #faang #fang #computerscience #cs #codingtiktok #coding #codinglife #boostofhope #fyp #codinginterview #softwareengineer #swe #tech #foryou #python #learntocode #google #techtok #programming #algorithms #learntocode #1318 @reper #foryou #viral #reper #urmaritori #for