LeetCode 75 C++ | Step-by-Step Solutions (LAN Academy) - LC 136 — Single Number (XOR Trick)

LeetCode 136 — Single Number (C++): The XOR Trick (O(n) / O(1)) If every number appears twice… how do you find the one that doesn’t — in linear time and constant space? This video shows the clean XOR pattern interviewers expect for LeetCode 136: Single Number. What you’ll learn: • The XOR properties that cancel pairs instantly • Why it works for any integers (including negatives) • A clean, minimal C++ implementation • Complexity + edge cases Key idea (XOR): a ^ a = 0 a ^ 0 = a So XOR-ing all values cancels duplicates and leaves the unique number. Complexity: Time: O(n) Extra space: O(1) Watch next (Bit Manipulation playlist): https://www.youtube.com/playlist?list=PLF0G-7pZcOza_jyAxwMpa5KnK3vST5smK Subscribe for more clear C++ LeetCode explanations: youtube.com/channel/UCdKpV0t_sLv9gUsxHOYrt7g?sub_confirmation=1 Video: https://youtu.be/ZTxFzZOQcrA #LeetCode #BitManipulation #XOR #CodingInterview #CPlusPlus #leetcodecoding #leetcodesolution #leetcodechallenge #faang #fang #computerscience #cs #codingtiktok #coding #codinglife #boostofhope #fyp #codinginterview #softwareengineer #swe #tech #foryou #python #learntocode #google #techtok #programming #algorithms #learntocode @reper #foryou #viral #reper #urmaritori #for