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Paint House - 2 (Many Colors) Dynamic Programming | Explained with Code
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DSA - Level 1 - Paint House - 2 (Many Colors) Dynamic Programming | Explained with Code

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  • 75 hours of video
  • Certificate of completion
  • Access on mobile and TV

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Please consume this content on nados.pepcoding.com for a richer experience. It is necessary to solve the questions while watching videos, nados.pepcoding.com enables that. NADOS also enables doubt support, career opportunities and contests besides free of charge content for learning. In this video, we discuss the paint house problem where we required paint all given houses in the minimum cost such that no adjacent houses are painted in the same color using dynamic programming. In this problem, 1. You are given a number n and a number k separated by a space, representing the number of houses and number of colors. 2. In the next n rows, you are given k space separated numbers representing the cost of painting nth house with one of the k colors. 3. You are required to calculate and print the minimum cost of painting all houses without painting any consecutive house with same color. To submit this problem, click here: https://www.pepcoding.com/resources/online-java-foundation/dynamic-programming-and-greedy/paint-house-many-colors-official/ojquestion For a better experience and more exercises, VISIT: https://www.pepcoding.com/resources/online-java-foundation #dp #dynamicprogramming Have a look at our result: https://www.pepcoding.com/placements Follow us on our FB page: https://www.facebook.com/pepcoding Follow us on Instagram: https://www.instagram.com/pepcoding Follow us on LinkedIn: https://www.linkedin.com/company/pepcoding-education

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