DSA - Level 1 - Climbing Stairs with Minimum Moves | Dynamic Programming Problem Explained

Please consume this content on nados.pepcoding.com for a richer experience. It is necessary to solve the questions while watching videos, nados.pepcoding.com enables that. NADOS also enables doubt support, career opportunities and contests besides free of charge content for learning. In this video, we discuss the solution of the Climb Stair in Minimum Moves problem where we are required to move from the ground level to the highest level with variable jumps and minimum move. In this problem, 1. You are given a number n, representing the number of stairs in a staircase. 2. You are on the 0th step and are required to climb to the top. 3. You are given n numbers, where ith element's value represents - till how far from the step you could jump to in a single move. You can of course jump fewer number of steps in the move. 4. You are required to print the number of minimum moves in which you can reach the top of staircase. Note - If there is no path through the staircase print null. #dp #dynamicprogramming #climbstairs For a better experience and more exercises, VISIT: https://www.pepcoding.com/resources/online-java-foundation Have a look at our result: https://www.pepcoding.com/placements Follow us on our FB page: https://www.facebook.com/pepcoding Follow us on Instagram: https://www.instagram.com/pepcoding Follow us on LinkedIn: https://www.linkedin.com/company/pepcoding-education