Solutions, acids, and bases | Chemistry | Khan Academy - Dilutions | Chemistry | Khan Academy

Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now! https://www.khanacademy.org/science/hs-chemistry/x2613d8165d88df5e:solutions-acids-and-bases/x2613d8165d88df5e:molarity/v/dilutions Want to explore more? Check out the full Solutions, acids, and bases playlist here: https://youtube.com/playlist?list=PLSQl0a2vh4HAHzfFIPU3q0hDdHKTEPrz5&si=ODwD0LbDD3IH8KdB Dilution is the process of lowering the concentration of a solution by adding solvent. This process is important for preparing solutions of precise concentrations for experiments. The dilution equation (M1*V1) = (M2*V2) is used to calculate the molarities and volumes required for the dilution. This often starts with a concentrated stock solution, which is then diluted to achieve the desired concentration for various experiments. Sections: 00:00 - Diluting Kool-aid 04:05 - Building the dilution equation 05:14 - Dilution practice problem 1 08:35 - Dilution practice problem 2 ------------------ Khan Academy is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We offer quizzes, questions, instructional videos, and articles on a range of academic subjects, including math, biology, chemistry, physics, history, economics, finance, grammar, preschool learning, and more. We provide teachers with tools and data so they can help their students develop the skills, habits, and mindsets for success in school and beyond. Khan Academy has been translated into dozens of languages, and 15 million people around the globe learn on Khan Academy every month. As a 501(c)(3) nonprofit organization, we would love your help! Donate or volunteer today! Donate here: https://donate.khanacademy.org/give/419869/#!/donation/checkout Volunteer here: https://www.khanacademy.org/contribute?utm_source=youtube&utm_medium=desc